经典的113道c语言题目及代码解释.docx

1 .输入两个正整数,m和n,求其最大公约数和最小公倍数，#inc1.udc<stdio.h>voidmain()Iinthcftint.ini)：尸函数声明*/int1.cd(intjntjnt)：/函数声明47intu,v>hj;Prin1.fr'P1.easeinput(wonumbers：n*);scanft"%d.%dM.&u,&v);h=hcf(u.v):Prin1.frHCF=%dn*h);I=Icd(Uxh);Prin1.T1.C.D=%d"J):)in(hcf'(incujntv)IiniUr:if(v>u)(t=uu=vv=ujwhi1.e(r=u%v)!=O)(u=vzv=r:)rcturn(v);im1.cd(i11u.intv.inth)Ircturn(u47);2 .输入一行字符,分别统计出其中字母、空格、数字和其他字符的个数,Winc1.udc<stdio.h>intIetteGdigitvSpacc,others;voidmain()Ivoidcount(char11):chartcxS();PrinifCT1.easeinputswing:nM);gc4s(ex1.);Printf(''string:5"):PUtSaCt);Ieuer-O;digi=O:SP1.KX=0:Othcrs=O;CoUn1.(IeX。；prin1.ftM1.e1.1.er:%d.digi(:,iid.space:%d.o1.hcrs:%(fne.1.e1.ter.digi1.spaceA>1.hers):voidcoun1.(charstr()Iinti;if<(s1.ri)>=,a'siri<=y>(s(ri)>=Wstr(!1.<=Z)>1.etter+:c1.scif(sir|iJ>='(r&&sir|i|<=V)digi(÷÷e1.seif(siri)=32)space+:e1.seothers+;>3 .输入一个正整数求出它是几位数：输出原数和位数C*inc1.de<s(dio.h>intdigit:voidmain()Ivoidcount(char();chartext(80:printfC*P1.easeinputnumbcrsn*);gcu(cxt);PriInfrNumbersAn,*);puts(iext);digit=O;count(cx();Prin1.frdigit%ddigi1.);voidcount(charstr)inii;for(i=0istr(i)!=<0'ii+)if(stri>=<0,str<=,9,)digit÷÷4 .钻入一个正整数.输出原数并逆序打印出各位数字#inc1.udc<stdio.h>voidinvef1.1.ongI11u1.ong);voidnain()Iunsigned1.ongiNumber;PriiHfr'P1.easeinputanuinber：nH);scanf("%1.d',.<iNurnber);prinf(',Theinputnumberis%1.dn,*.iNumber);prin1.f("Theinversenumberis:")：invcrt1.ong1.nt(iNumber);voidinvet1.ongInUongx)Iif(x>=(Mkx<=9)primtr'%dn,x);e1.se(printf(,'%d".x%10);invcrt1.ongInt(x1.O);J)5 .从键盘上输入假设干学生的一门课成绩，统计并输出最高成绩和最低成绩及相应的序号,当输入负数时结束输入.6 .从键盘上输入假设干学生的一门课成绩，计算出平均分，当输入仪数时结未输入。将结果输出。7 .求1.!+2!+3!+20!.凡结果输出.#inc1.udc<stdio.h>voidmain。If1.oats=O.t=1.;intn;fbr(n=1.;n<=20;n+)(t=tn:S=S1H；)Prin1.frI!÷2!+3!+.+20!-%Cw：8 .打印以以下图案：案Winc1.de<sidio.h>voidnain()Iinti,j;PrinIfCThepictureisnw);sia1.iccharpiciurc(4J7=(V7V*a.1«t<1.t,於,：*,11.I1.1.1.JI»for(i=0；i<=3；i+)fortj=0<=6÷÷)printf("%cvic<ufeiU):Primfrr):J9 .打印以以下图案:#inC1.UdCVs【d心.h>voidmain()i11ti.j；Printf("Thepictureis:n*);charpicturc4114=(*'hIJ案:*:拿.於产，:，和).fr(i=OJ<=3zi+)for(j=OJ<=3÷÷)printf("%cpicturei);Primfer):J10 .求以下试子的值，112+1314+1/99-1/100.将结果输出。Winc1.udc<stdio.h>voidmain()f1.oatsum=1.0.1.,s=i:inti;for(i三Ui<=100i+÷)I=Hksum=sum+t:s=-s;Jprin1.f(',h1.2+1.3-1.44-+1./99-1./100=%5.4nnM.sum>:11 .打印出100999之间的所有水仙花数。析nc1.ude<stdi<>.h>voidnain()inti.j.k.n：Pri1.Mf1.n00799之间的所有水仙花数am:W');fbr(n=100n<1000n÷+)(i=n1.:j=n10-i0;k=n%IO;if«n=产i*i+j与专+kk*k)PrintR'%d,n);Iprinf("n,);>12 .求Sn=a÷aa*aaa÷÷aaa之tf1.，n,a由雄盘输入C*inc1.de<s(dio.h>voidmain()Iinta,n.i=1.3n=jn=();prinif('*a.n=:H);SCanfr%d%d”.&a&n)：whi1.c(i<=n)(n=tn+a;sn=sn+tn:a=a*10;+i；>Prin1.R“d+aa+aaa+.+aa.a-%dn,*.sn):)13 .打印以以下图案：*拿分*衾*衾#inc1.uck<s1.dio.h>voidmain()JChara1.7=咒'叫*.f产');inti.j.k:charspace=',:Prin1.frThCpicturefbf(i=0u<4u+)prin<f("'n");primf("");for(j=1.y<=ij+)printftj"%c*,space);fortk=0;k<7;k+)Prin1.fr%cf1.:JprintfCn");14 .打印以以下图案：112112321123432I15 .打印以以下图案：123432112321121I16 .编写一个统计学生成绩程序,完成以下功能：输入4个学生的2门课成绩：求出全班的总平均分.将结果输出。#inc1.ude<s1.dio.h>WdcfincN4structstudentIcharnum(3:charnamc4;f1.oatscorc2;f1.oatavr;>s1.uN:voidmain()Iintij;f1.oatsum,avcragc;f<x(i=Oii<Nii÷÷)产输入数据军(Printtrinputscoresofstudcnt%dzn"J÷1.);prinif(*'namc:w);$canfC%sM.$tui|.nan)e);fortj=0<2÷+)PrinWSCore%d:"J+1);scanf(,%stui.scorcyj):Iavcragc=0;/计口/for(i=Oi<NJ÷÷)(SUm=O:fortj=0y<2zj÷÷)sum÷=su(i.scorc(j;stui,avr=sun2;average+=stuij.avr:)average/=N;rinfC,NamescoreIscoe2average”);fr(i=OJ<Ni+)(primf(N%5s%IOsN.stui|.numt$tui.namc);for(j=0<2÷÷)p11n1.f(,'%9.2,.s(ui).sc>rcj);printiV%8.2fn*.stu|i|.avr);Iprinif(',average=%5.2nnM.average);>17 .打印以以下图案:*号*8qindudc<s1.d心.h>voidmain()JChara51=F'叫*.*；*:inti,j.k;charspace=',:printft''Thcpicturei$:w);fb<(i=0d<5u+÷)(printf(n"):printf(""Xfor(j=1.<=iy+)p11ntft"".space);fortk=0k<5k+÷)printft"%c-.a(kh：JPrintfrW);1.&给出年月.t1.计算该H是该年的第几天.#inc1.ude<stdio.h>voidI1.1.ainOintsum_day(int.int);int1.cap(intyear);intyear,n>nh.day.days;prin1.ft,*inputda1.e(year.mnth.day>:*):scanf("od.id.%d*.Aycar.month.day):prinf,%d'%d.(d*,ycar.monch.day);days=sum.day(n>onh.day);if(kap<year>&&mun1.h>=3)days=days+1：PrinIfnSthe%dthdayin(hisyear.W,days);intsum-day(intnwnth.mtday>IimdayJabU3三三0,3128,313031.30,31,31,30,3130,31;inti;for(i=1.zi<11>n1.hu÷+)day+=day_tah|i|:rcturn(day);>int1.eap(intyear)I