c语言练习题——循环和数组.docx
C语言练习题一一循环及数组1 .求IoOO之内的所有完数2 .输入两个正整数m和n,求其最大公约数和最小公倍数。3 .求1!+2!+3!+4!+20!4 .用for循环求分数序列：2/1,3/2,5/3,8/5,13/8,21/13,，前20项之和。5 .打印杨辉三角形。6 .输入5个学生的数学、语文、英语3门课程的成绩，计算并输出每一门课程的平均成绩和每一位学生的平均成绩7 .求一个3*3的整型矩阵对角线元素之和。8 .编程计算mXs阶矩阵A和SXn阶矩阵B之积9 .任意输入n个从小到大的整数的数列，然后输入一个整数插入到数列中，使数列保持从小到大的顺序10 .编写程序键盘输入整型变量n,从低位开始取出整型变量n偶数位上的数依次放在整型变量s中，然后输出So例如：当n中的数为：87654321时,S中的数为：8642。输入样例：87654321输出样例：86421 .程序代码：include<stdio.h>intmain()intn,sum,i;for(n=1;n<=1000;n+)(sum=0;for(i=1;i<n;i+)if(n%i=0)sum=sum+i;)if(sum=n)(printf(z,%d",n);)returnO;)运行结果：628496Processexitedafter0.1057secondswithreturnvalue0请按任意键继续.2 .程序代码：ttinclude<stdio.h>intmain(void)*Begin*/intm,n,a>b,t;scanf("%d%d”,&m,&n);t=m%n;if(m<n)t=m;m=n;n=t;a=m;b=n;while(b!=0)(t=a%b;a=b;b=t;)Printf(最大公约数是:ln最小公倍数是:%d,a,m*n/a);return0;)运行结果：1436最大公约数是:2最小公倍数是:252Processexitedafter6.193secondswithreturnvalue0请按任意键继续.3 .程序代码：#include<stdio.h>intmain()inti;doublef=l,sum=0;for(i=l;i<=20;i+)f=f*i;sum+=f;printf(z,%fz,sum);return0;)运行结果：2561327494111820300.000000Processexitedafter0.03475secondswithreturnvalue0请按任意键继续.4 .程序代码include<stdio.h>intmain()inti;doublea,b,s,t;a=2;b=l;s=ab;for(i=l;i<20;i+)t=b;b=a;a=a+t;s=s+ab;printf(*sum=%.21fn/z,s);returnO;运行结果sum=32.66Processexitedafter0.03287secondswithreturnvalue0请按任意键继续.5.程序代码include<stdio.h>defineN50intmain()(intaNN,i,j,n;scanf(飞d”,&n);输入打印行数for(i=0;i<=n;i+)ai0=l;ai=1;for(i=l;i<n;i+)for(j=l;j<n;j+)(aij=ai-lj+ai-lj-l;)for(i=0;i<n;i+)for(j=0;j<i+l;j+)printf(*%dt*,aij);Printf("n");return0;运行结果611112113311464115101051Processexitedafter12.06secondswithreturnvalue0请按任意键继续.6.程序代码ttinclude<stdio.h>defineM5#defineN3intmainO(/*Begi*/doubleaverage,sum;intaMN,i,j;for(i=0;i<M;i+)for(j=0J<NJ+)scanfCz%d,&aij);)Printf(“每个学生的平均分：n");for(i=0;i<M;i+)(for(j=0,sum=0;j<N;j+)(sum+=aij;average=sumN;printf%d*,aij);)Printf("%.If”,average);printf(n);)Printf(每门课的平均分:n");for(j=0;j<N;j+)(for(i=0,sum=0;i<M;i+)(sum+=aij;average=sumM;)printf(z,%.If”,average);return0;)运行结果857888609080917992508483458680每个学生的平均分：85788883.760908076.791799287.350848372.345868070.3每门课的平均分:66.283.484.6Processexitedafter19.6secondswithreturnvalue0请按任意键继续.7.程序代码ttinclude<stdio.h>intmain()inta33;inti,j；intsum;for(i=0;i<3;i+)for(j=0;j<3;j+)scanf(*%d*,&aij);for(i=0;i<3;i+)for(j=0;j<3;j+)if(i=j)II(i+j=2)sum=sum+aij;printf(z,%dz,sum);return0;)运行结果12345678925Processexitedafter25.93secondswithreturnvalue0请按任意键继续.8.程序代码#include<stdio.h>Sinclude<stdlib.h>#defineM10defineS10ttdefineN10intmain()/*Begin*/intaMS,bSM,cMN,i,j,k;intm,s,n;scanf(飞d”,&m);scanf(z,%dz,&s);scanf("%d",&n);for(i=0;i<m;i+)for(j=0;j<s;j+)scanf(zz%d,&aij);)for(i=0;i<s;i+)for(j=0;j<n;j+)SCanf("%c,&bij);)for(i=0;i<m;i÷+)(for(j=0;j<n;j+)(cij=0;for(k=0;k<s;k+)cij=cij+aik*bkj)for(i=0;i<m;i+)for(j=0;j<n;j+)printf(*%dt*,cij);printf(z,nz,);/*End*/return0;)运行结果323231-2311-2-32-108-7-6-30-35-7-9Processexitedafter21.96secondswithreturnvalue0请按任意键继续.9.程序代码#include<stdio.h>defineN100intmain()/*Begin*/intaN,i,n,x,j;scanf("%dn”,&n);for(i=0;i<n;i+)scanf("%dn”,ftai);scanf(*%d*,&x);while(aj<=x&&j<n)(j+;找不到比x大的元素时也要退出循环)for(i=n-l;i>=j;i-)(ai+l=ai;aj=x;for(i=0;i<=n;i+)printf(*%d”,ai);/*End*/return0;)运行结果1010154252596467738288601015425259606467738288Processexitedafter1.863secondswithreturnvalue0请按任意键继续.10.程序代码#include<stdio.h>intmain()intn;scanf("%c,&n);ints=0,i=l;while(n!=O)=1O;s+=n%10*i;这样就能够输出偶数位的数字了i*=10;n=10;)Printf(",s);return0;)运行结果876543218642Processexitedafter13.67secondswithreturnvalue0请按任意键继续.
